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Re: How many extra revs for every extra tooth?
Posted by 'SimonS' on 25 Nov 2009 @ 11:21


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SimonS
Joined: December 2004
Total Posts: 4
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"Racing F Blue, I gain 400rpm for each tooth I go up."

Mechanically that is impossible, though the calculations assume that you are reaching a constant maximum speed.

Gaining 400 rpm for every tooth increased would imply that you were so far up the gearing that each tooth meant the kart was going faster at the point of measurement.

It is a simple calculation. The revs * the gear ratio= the rpm of the rear axle. To maintain the same rear axle rpm with a 1 tooth difference in the gearing takes an increase of 200 rpm. If you are seeing 400 rpm increase, then the rear axle must be turning faster, hence you are going quicker at that point.

Normally one might expect a rise in speed while increasing teeth to mean quicker lap times, and if it doesn't produce quicker lap times then there must be something else in play. Possibly you are seeing the higher revs going down the hill at GyG or perhaps your highest engine revs are caused by being in the air, not on the track, (which is often the case, if you have one lap with a significantly higher revs than the others)

Message Thread:

How many extra revs for every extra tooth?  by 'Attack2001'   (21 Nov 2009 @ 20:48)
Re: How many extra revs for every extra tooth?  by 'QuickOldTimer'   (21 Nov 2009 @ 21:09)
Re: How many extra revs for every extra tooth?  by 'buzzinrussell'   (21 Nov 2009 @ 22:05)
Re: How many extra revs for every extra tooth?  by 'JCC'   (22 Nov 2009 @ 17:30)
Re: How many extra revs for every extra tooth?  by 'SimonS'   (22 Nov 2009 @ 17:47)
Re: How many extra revs for every extra tooth?  by 'GillardKid'   (23 Nov 2009 @ 21:54)
Re: How many extra revs for every extra tooth?  by 'SimonS'  << You are here!

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